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Read how can I find out the same word in a text if it has different case (u

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Question: How can I find out the same word in a text if it has different case (upper or lower ) in different places?

It can be written even like this "w o r d " instead of "word". I need t o write my dictionary function. The methods equals() or compareto() from String class do not help me much.. I need to get some "natural feeling" function of the same word in different cases..

Answer: To get natural language comparison of two strings (words) you need to use the Collator class (java.textCollator). This class lets to compare the words for all the cases described in your question.

With compare() function you can find who is first and who is second for two words. If they have the same position in natural row of words it means the they are the same:

Collator ourCollator = Collator.getInstance();
if( ourCollator.compare("abcdefgeeeee", "ABCDEFGEEEEE") < 0 )
    System.out.println("abcdefgeeeee is less than ABCDEFGEEEEE");
else if ( ourCollator.compare("abcdefgeeeee", "ABCDEFGEEEEE") > 0 )
    System.out.println("abcdefgeeeee is greater than or equal to ABCDEFGEEEEE");
else System.out.println("Words are equivalent");

The Collator class is good if you compare words one or few times... If you need to compare words many times for better performance the CollationKey class is better choice. It converts words into bits sequence and do comparison bitwise, which is significantly faster!

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