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File path in web application on Tomcat? Take the solution and code example!

JavaFAQ Home » JSP, Servlets Go to all tips in JSP, Servlets

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Question: How do I find a real path to a file in my JSP application?

Since JSP is compiled to a servlet I tried to use " getServletContext().getRealPath ("/"); " but it causes a compilation error. Very strange...What is matter?

Answer: Yes, indeed in your servlet you can use the next code snippet and it works ok:


String configFilePath = getServletContext().getRealPath("/");
configFilePath += File.separator + "some directory here" + File.separator + "myfile.txt";

Despite to fact that all JSPs are compiled into servlets (you can find them under "work/Catalina/localhost/YourWebappsName" directory) java will does not know about "application" ..

Here is another solution for your JSP code:


But if you use a JSP you need another code, which perfectly works:


String path = application.getRealPath("/");
String pathSeparator = File.separator; // will return either "\" or "/", depends on OS
String myFilePath = "some dir" + pathSeparator + "myfile.txt";
String fullPath = path + myFilePath;

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